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2011年9月5日 星期一

[ASP.NET MVC] 如何在View中 Post List型別的參數給Controoler

方法很簡單,只要把對應的input name設定成陣列的型態就可以了,範例:










[HttpPost]
public ActionResult PrintBarcode( List< Models.test > cmd)
{
...
}
class Test{
public long ProductId { get; set; }
public int Quantity { get; set; }
}


Post時候參數如果透過JQuery,則可以直接把form給序列化: $('#formId').serialize()



Reference:http://kristofmattei.be/2009/10/19/asp-net-mvc-model-binding-to-a-list/http://blog.gfader.com/2010/05/aspnet-mvc-model-binding-to-list-or-how.html

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